7(x+2)+3(x-4)=32

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Solution for 7(x+2)+3(x-4)=32 equation: 



7(x+2)+3(x-4)=32

We move all terms to the left:

7(x+2)+3(x-4)-(32)=0

We multiply parentheses

7x+3x+14-12-32=0

We add all the numbers together, and all the variables

10x-30=0

We move all terms containing x to the left, all other terms to the right

10x=30

x=30/10

x=3

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