7(x+2)+3x=12-2(5x-7)

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Solution for 7(x+2)+3x=12-2(5x-7) equation: 



7(x+2)+3x=12-2(5x-7)

We move all terms to the left:

7(x+2)+3x-(12-2(5x-7))=0

We add all the numbers together, and all the variables

3x+7(x+2)-(12-2(5x-7))=0

We multiply parentheses

3x+7x-(12-2(5x-7))+14=0



We calculate terms in parentheses: -(12-2(5x-7)), so:

12-2(5x-7)

determiningTheFunctionDomain
-2(5x-7)+12

We multiply parentheses

-10x+14+12

We add all the numbers together, and all the variables

-10x+26

Back to the equation:

-(-10x+26)



We add all the numbers together, and all the variables

10x-(-10x+26)+14=0

We get rid of parentheses

10x+10x-26+14=0

We add all the numbers together, and all the variables

20x-12=0

We move all terms containing x to the left, all other terms to the right

20x=12

x=12/20

x=3/5

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