7(x+2)+4=-7(x-2)-7

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Solution for 7(x+2)+4=-7(x-2)-7 equation: 



7(x+2)+4=-7(x-2)-7

We move all terms to the left:

7(x+2)+4-(-7(x-2)-7)=0

We multiply parentheses

7x-(-7(x-2)-7)+14+4=0



We calculate terms in parentheses: -(-7(x-2)-7), so:

-7(x-2)-7

We multiply parentheses

-7x+14-7

We add all the numbers together, and all the variables

-7x+7

Back to the equation:

-(-7x+7)



We add all the numbers together, and all the variables

7x-(-7x+7)+18=0

We get rid of parentheses

7x+7x-7+18=0

We add all the numbers together, and all the variables

14x+11=0

We move all terms containing x to the left, all other terms to the right

14x=-11

x=-11/14

x=-11/14

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