7(x+2)+4x=6(2x-4)

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Solution for 7(x+2)+4x=6(2x-4) equation:



7(x+2)+4x=6(2x-4)
We move all terms to the left:
7(x+2)+4x-(6(2x-4))=0
We add all the numbers together, and all the variables
4x+7(x+2)-(6(2x-4))=0
We multiply parentheses
4x+7x-(6(2x-4))+14=0
We calculate terms in parentheses: -(6(2x-4)), so:
6(2x-4)
We multiply parentheses
12x-24
Back to the equation:
-(12x-24)
We add all the numbers together, and all the variables
11x-(12x-24)+14=0
We get rid of parentheses
11x-12x+24+14=0
We add all the numbers together, and all the variables
-1x+38=0
We move all terms containing x to the left, all other terms to the right
-x=-38
x=-38/-1
x=+38

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