7(x+2)+5x=3+2(x-4)

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Solution for 7(x+2)+5x=3+2(x-4) equation: 



7(x+2)+5x=3+2(x-4)

We move all terms to the left:

7(x+2)+5x-(3+2(x-4))=0

We add all the numbers together, and all the variables

5x+7(x+2)-(3+2(x-4))=0

We multiply parentheses

5x+7x-(3+2(x-4))+14=0



We calculate terms in parentheses: -(3+2(x-4)), so:

3+2(x-4)

determiningTheFunctionDomain
2(x-4)+3

We multiply parentheses

2x-8+3

We add all the numbers together, and all the variables

2x-5

Back to the equation:

-(2x-5)



We add all the numbers together, and all the variables

12x-(2x-5)+14=0

We get rid of parentheses

12x-2x+5+14=0

We add all the numbers together, and all the variables

10x+19=0

We move all terms containing x to the left, all other terms to the right

10x=-19

x=-19/10

x=-1+9/10

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