7(x+2)+8(x-3)=2(x+2)

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Solution for 7(x+2)+8(x-3)=2(x+2) equation: 



7(x+2)+8(x-3)=2(x+2)

We move all terms to the left:

7(x+2)+8(x-3)-(2(x+2))=0

We multiply parentheses

7x+8x-(2(x+2))+14-24=0



We calculate terms in parentheses: -(2(x+2)), so:

2(x+2)

We multiply parentheses

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

15x-(2x+4)-10=0

We get rid of parentheses

15x-2x-4-10=0

We add all the numbers together, and all the variables

13x-14=0

We move all terms containing x to the left, all other terms to the right

13x=14

x=14/13

x=1+1/13

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