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7(x+2)+8(x-3)=2(x+2)
We move all terms to the left:
7(x+2)+8(x-3)-(2(x+2))=0
We multiply parentheses
7x+8x-(2(x+2))+14-24=0
We calculate terms in parentheses: -(2(x+2)), so:We add all the numbers together, and all the variables
2(x+2)
We multiply parentheses
2x+4
Back to the equation:
-(2x+4)
15x-(2x+4)-10=0
We get rid of parentheses
15x-2x-4-10=0
We add all the numbers together, and all the variables
13x-14=0
We move all terms containing x to the left, all other terms to the right
13x=14
x=14/13
x=1+1/13
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