7(x+2)-(x-4)=-2(5-x)+16

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Solution for 7(x+2)-(x-4)=-2(5-x)+16 equation: 



7(x+2)-(x-4)=-2(5-x)+16

We move all terms to the left:

7(x+2)-(x-4)-(-2(5-x)+16)=0

We add all the numbers together, and all the variables

7(x+2)-(x-4)-(-2(-1x+5)+16)=0

We multiply parentheses

7x-(x-4)-(-2(-1x+5)+16)+14=0

We get rid of parentheses

7x-x-(-2(-1x+5)+16)+4+14=0



We calculate terms in parentheses: -(-2(-1x+5)+16), so:

-2(-1x+5)+16

We multiply parentheses

2x-10+16

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

6x-(2x+6)+18=0

We get rid of parentheses

6x-2x-6+18=0

We add all the numbers together, and all the variables

4x+12=0

We move all terms containing x to the left, all other terms to the right

4x=-12

x=-12/4

x=-3

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