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7(x+2)-1=3x+4(3+x)
We move all terms to the left:
7(x+2)-1-(3x+4(3+x))=0
We add all the numbers together, and all the variables
7(x+2)-(3x+4(x+3))-1=0
We multiply parentheses
7x-(3x+4(x+3))+14-1=0
We calculate terms in parentheses: -(3x+4(x+3)), so:We add all the numbers together, and all the variables
3x+4(x+3)
We multiply parentheses
3x+4x+12
We add all the numbers together, and all the variables
7x+12
Back to the equation:
-(7x+12)
7x-(7x+12)+13=0
We get rid of parentheses
7x-7x-12+13=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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