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7(x+2)-3(2x+1)=21
We move all terms to the left:
7(x+2)-3(2x+1)-(21)=0
We multiply parentheses
7x-6x+14-3-21=0
We add all the numbers together, and all the variables
x-10=0
We move all terms containing x to the left, all other terms to the right
x=10
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