7(x+2)-3=2(x+2)+17

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Solution for 7(x+2)-3=2(x+2)+17 equation: 



7(x+2)-3=2(x+2)+17

We move all terms to the left:

7(x+2)-3-(2(x+2)+17)=0

We multiply parentheses

7x-(2(x+2)+17)+14-3=0



We calculate terms in parentheses: -(2(x+2)+17), so:

2(x+2)+17

We multiply parentheses

2x+4+17

We add all the numbers together, and all the variables

2x+21

Back to the equation:

-(2x+21)



We add all the numbers together, and all the variables

7x-(2x+21)+11=0

We get rid of parentheses

7x-2x-21+11=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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