7(x+2)-3=25+(3x-4)

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Solution for 7(x+2)-3=25+(3x-4) equation: 



7(x+2)-3=25+(3x-4)

We move all terms to the left:

7(x+2)-3-(25+(3x-4))=0

We multiply parentheses

7x-(25+(3x-4))+14-3=0



We calculate terms in parentheses: -(25+(3x-4)), so:

25+(3x-4)

determiningTheFunctionDomain
(3x-4)+25

We get rid of parentheses

3x-4+25

We add all the numbers together, and all the variables

3x+21

Back to the equation:

-(3x+21)



We add all the numbers together, and all the variables

7x-(3x+21)+11=0

We get rid of parentheses

7x-3x-21+11=0

We add all the numbers together, and all the variables

4x-10=0

We move all terms containing x to the left, all other terms to the right

4x=10

x=10/4

x=2+1/2

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