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7(x+2)-5=2x+5(1+x)
We move all terms to the left:
7(x+2)-5-(2x+5(1+x))=0
We add all the numbers together, and all the variables
7(x+2)-(2x+5(x+1))-5=0
We multiply parentheses
7x-(2x+5(x+1))+14-5=0
We calculate terms in parentheses: -(2x+5(x+1)), so:We add all the numbers together, and all the variables
2x+5(x+1)
We multiply parentheses
2x+5x+5
We add all the numbers together, and all the variables
7x+5
Back to the equation:
-(7x+5)
7x-(7x+5)+9=0
We get rid of parentheses
7x-7x-5+9=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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