7(x+2)-8=10+2(x-4)

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Solution for 7(x+2)-8=10+2(x-4) equation: 



7(x+2)-8=10+2(x-4)

We move all terms to the left:

7(x+2)-8-(10+2(x-4))=0

We multiply parentheses

7x-(10+2(x-4))+14-8=0



We calculate terms in parentheses: -(10+2(x-4)), so:

10+2(x-4)

determiningTheFunctionDomain
2(x-4)+10

We multiply parentheses

2x-8+10

We add all the numbers together, and all the variables

2x+2

Back to the equation:

-(2x+2)



We add all the numbers together, and all the variables

7x-(2x+2)+6=0

We get rid of parentheses

7x-2x-2+6=0

We add all the numbers together, and all the variables

5x+4=0

We move all terms containing x to the left, all other terms to the right

5x=-4

x=-4/5

x=-4/5

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