7(x+2)=(x+12)-2

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Solution for 7(x+2)=(x+12)-2 equation:



7(x+2)=(x+12)-2
We move all terms to the left:
7(x+2)-((x+12)-2)=0
We multiply parentheses
7x-((x+12)-2)+14=0
We calculate terms in parentheses: -((x+12)-2), so:
(x+12)-2
We get rid of parentheses
x+12-2
We add all the numbers together, and all the variables
x+10
Back to the equation:
-(x+10)
We get rid of parentheses
7x-x-10+14=0
We add all the numbers together, and all the variables
6x+4=0
We move all terms containing x to the left, all other terms to the right
6x=-4
x=-4/6
x=-2/3

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