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7(x+2)=-2(5x-4)+x
We move all terms to the left:
7(x+2)-(-2(5x-4)+x)=0
We multiply parentheses
7x-(-2(5x-4)+x)+14=0
We calculate terms in parentheses: -(-2(5x-4)+x), so:We get rid of parentheses
-2(5x-4)+x
We add all the numbers together, and all the variables
x-2(5x-4)
We multiply parentheses
x-10x+8
We add all the numbers together, and all the variables
-9x+8
Back to the equation:
-(-9x+8)
7x+9x-8+14=0
We add all the numbers together, and all the variables
16x+6=0
We move all terms containing x to the left, all other terms to the right
16x=-6
x=-6/16
x=-3/8
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