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7(x+2)=3(2x-5)
We move all terms to the left:
7(x+2)-(3(2x-5))=0
We multiply parentheses
7x-(3(2x-5))+14=0
We calculate terms in parentheses: -(3(2x-5)), so:We get rid of parentheses
3(2x-5)
We multiply parentheses
6x-15
Back to the equation:
-(6x-15)
7x-6x+15+14=0
We add all the numbers together, and all the variables
x+29=0
We move all terms containing x to the left, all other terms to the right
x=-29
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