7(x+2)=3(x-12)-2

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Solution for 7(x+2)=3(x-12)-2 equation: 



7(x+2)=3(x-12)-2

We move all terms to the left:

7(x+2)-(3(x-12)-2)=0

We multiply parentheses

7x-(3(x-12)-2)+14=0



We calculate terms in parentheses: -(3(x-12)-2), so:

3(x-12)-2

We multiply parentheses

3x-36-2

We add all the numbers together, and all the variables

3x-38

Back to the equation:

-(3x-38)



We get rid of parentheses

7x-3x+38+14=0

We add all the numbers together, and all the variables

4x+52=0

We move all terms containing x to the left, all other terms to the right

4x=-52

x=-52/4

x=-13

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