7(x+2)=4(2x+3)

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Solution for 7(x+2)=4(2x+3) equation: 



7(x+2)=4(2x+3)

We move all terms to the left:

7(x+2)-(4(2x+3))=0

We multiply parentheses

7x-(4(2x+3))+14=0



We calculate terms in parentheses: -(4(2x+3)), so:

4(2x+3)

We multiply parentheses

8x+12

Back to the equation:

-(8x+12)



We get rid of parentheses

7x-8x-12+14=0

We add all the numbers together, and all the variables

-1x+2=0

We move all terms containing x to the left, all other terms to the right

-x=-2

x=-2/-1

x=+2

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