7(x+2)=5(x-2)+2(x+12)

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Solution for 7(x+2)=5(x-2)+2(x+12) equation:


Simplifying
7(x + 2) = 5(x + -2) + 2(x + 12)

Reorder the terms:
7(2 + x) = 5(x + -2) + 2(x + 12)
(2 * 7 + x * 7) = 5(x + -2) + 2(x + 12)
(14 + 7x) = 5(x + -2) + 2(x + 12)

Reorder the terms:
14 + 7x = 5(-2 + x) + 2(x + 12)
14 + 7x = (-2 * 5 + x * 5) + 2(x + 12)
14 + 7x = (-10 + 5x) + 2(x + 12)

Reorder the terms:
14 + 7x = -10 + 5x + 2(12 + x)
14 + 7x = -10 + 5x + (12 * 2 + x * 2)
14 + 7x = -10 + 5x + (24 + 2x)

Reorder the terms:
14 + 7x = -10 + 24 + 5x + 2x

Combine like terms: -10 + 24 = 14
14 + 7x = 14 + 5x + 2x

Combine like terms: 5x + 2x = 7x
14 + 7x = 14 + 7x

Add '-14' to each side of the equation.
14 + -14 + 7x = 14 + -14 + 7x

Combine like terms: 14 + -14 = 0
0 + 7x = 14 + -14 + 7x
7x = 14 + -14 + 7x

Combine like terms: 14 + -14 = 0
7x = 0 + 7x
7x = 7x

Add '-7x' to each side of the equation.
7x + -7x = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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