7(x+3)+16=2(x-5)

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Solution for 7(x+3)+16=2(x-5) equation: 



7(x+3)+16=2(x-5)

We move all terms to the left:

7(x+3)+16-(2(x-5))=0

We multiply parentheses

7x-(2(x-5))+21+16=0



We calculate terms in parentheses: -(2(x-5)), so:

2(x-5)

We multiply parentheses

2x-10

Back to the equation:

-(2x-10)



We add all the numbers together, and all the variables

7x-(2x-10)+37=0

We get rid of parentheses

7x-2x+10+37=0

We add all the numbers together, and all the variables

5x+47=0

We move all terms containing x to the left, all other terms to the right

5x=-47

x=-47/5

x=-9+2/5

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