7(x+3)+1=2x+5(4+x)

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Solution for 7(x+3)+1=2x+5(4+x) equation:


Simplifying
7(x + 3) + 1 = 2x + 5(4 + x)

Reorder the terms:
7(3 + x) + 1 = 2x + 5(4 + x)
(3 * 7 + x * 7) + 1 = 2x + 5(4 + x)
(21 + 7x) + 1 = 2x + 5(4 + x)

Reorder the terms:
21 + 1 + 7x = 2x + 5(4 + x)

Combine like terms: 21 + 1 = 22
22 + 7x = 2x + 5(4 + x)
22 + 7x = 2x + (4 * 5 + x * 5)
22 + 7x = 2x + (20 + 5x)

Reorder the terms:
22 + 7x = 20 + 2x + 5x

Combine like terms: 2x + 5x = 7x
22 + 7x = 20 + 7x

Add '-7x' to each side of the equation.
22 + 7x + -7x = 20 + 7x + -7x

Combine like terms: 7x + -7x = 0
22 + 0 = 20 + 7x + -7x
22 = 20 + 7x + -7x

Combine like terms: 7x + -7x = 0
22 = 20 + 0
22 = 20

Solving
22 = 20

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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