7(x+3)+1=8(x+2)+2

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Solution for 7(x+3)+1=8(x+2)+2 equation: 



7(x+3)+1=8(x+2)+2

We move all terms to the left:

7(x+3)+1-(8(x+2)+2)=0

We multiply parentheses

7x-(8(x+2)+2)+21+1=0



We calculate terms in parentheses: -(8(x+2)+2), so:

8(x+2)+2

We multiply parentheses

8x+16+2

We add all the numbers together, and all the variables

8x+18

Back to the equation:

-(8x+18)



We add all the numbers together, and all the variables

7x-(8x+18)+22=0

We get rid of parentheses

7x-8x-18+22=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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