7(x+3)+2=-7(x+4)-7

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Solution for 7(x+3)+2=-7(x+4)-7 equation: 



7(x+3)+2=-7(x+4)-7

We move all terms to the left:

7(x+3)+2-(-7(x+4)-7)=0

We multiply parentheses

7x-(-7(x+4)-7)+21+2=0



We calculate terms in parentheses: -(-7(x+4)-7), so:

-7(x+4)-7

We multiply parentheses

-7x-28-7

We add all the numbers together, and all the variables

-7x-35

Back to the equation:

-(-7x-35)



We add all the numbers together, and all the variables

7x-(-7x-35)+23=0

We get rid of parentheses

7x+7x+35+23=0

We add all the numbers together, and all the variables

14x+58=0

We move all terms containing x to the left, all other terms to the right

14x=-58

x=-58/14

x=-4+1/7

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