7(x+3)+2=58

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Solution for 7(x+3)+2=58 equation: 



7(x+3)+2=58

We move all terms to the left:

7(x+3)+2-(58)=0

We add all the numbers together, and all the variables

7(x+3)-56=0

We multiply parentheses

7x+21-56=0

We add all the numbers together, and all the variables

7x-35=0

We move all terms containing x to the left, all other terms to the right

7x=35

x=35/7

x=5

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