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7(x+3)+3=-5(x-6)-5
We move all terms to the left:
7(x+3)+3-(-5(x-6)-5)=0
We multiply parentheses
7x-(-5(x-6)-5)+21+3=0
We calculate terms in parentheses: -(-5(x-6)-5), so:We add all the numbers together, and all the variables
-5(x-6)-5
We multiply parentheses
-5x+30-5
We add all the numbers together, and all the variables
-5x+25
Back to the equation:
-(-5x+25)
7x-(-5x+25)+24=0
We get rid of parentheses
7x+5x-25+24=0
We add all the numbers together, and all the variables
12x-1=0
We move all terms containing x to the left, all other terms to the right
12x=1
x=1/12
x=1/12
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