7(x+3)+3x+1=2(x-13)

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Solution for 7(x+3)+3x+1=2(x-13) equation:


Simplifying
7(x + 3) + 3x + 1 = 2(x + -13)

Reorder the terms:
7(3 + x) + 3x + 1 = 2(x + -13)
(3 * 7 + x * 7) + 3x + 1 = 2(x + -13)
(21 + 7x) + 3x + 1 = 2(x + -13)

Reorder the terms:
21 + 1 + 7x + 3x = 2(x + -13)

Combine like terms: 21 + 1 = 22
22 + 7x + 3x = 2(x + -13)

Combine like terms: 7x + 3x = 10x
22 + 10x = 2(x + -13)

Reorder the terms:
22 + 10x = 2(-13 + x)
22 + 10x = (-13 * 2 + x * 2)
22 + 10x = (-26 + 2x)

Solving
22 + 10x = -26 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
22 + 10x + -2x = -26 + 2x + -2x

Combine like terms: 10x + -2x = 8x
22 + 8x = -26 + 2x + -2x

Combine like terms: 2x + -2x = 0
22 + 8x = -26 + 0
22 + 8x = -26

Add '-22' to each side of the equation.
22 + -22 + 8x = -26 + -22

Combine like terms: 22 + -22 = 0
0 + 8x = -26 + -22
8x = -26 + -22

Combine like terms: -26 + -22 = -48
8x = -48

Divide each side by '8'.
x = -6

Simplifying
x = -6

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