7(x+3)+5=10(x+2)+3

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Solution for 7(x+3)+5=10(x+2)+3 equation: 



7(x+3)+5=10(x+2)+3

We move all terms to the left:

7(x+3)+5-(10(x+2)+3)=0

We multiply parentheses

7x-(10(x+2)+3)+21+5=0



We calculate terms in parentheses: -(10(x+2)+3), so:

10(x+2)+3

We multiply parentheses

10x+20+3

We add all the numbers together, and all the variables

10x+23

Back to the equation:

-(10x+23)



We add all the numbers together, and all the variables

7x-(10x+23)+26=0

We get rid of parentheses

7x-10x-23+26=0

We add all the numbers together, and all the variables

-3x+3=0

We move all terms containing x to the left, all other terms to the right

-3x=-3

x=-3/-3

x=1

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