7(x+3)+5=6(x-2)

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Solution for 7(x+3)+5=6(x-2) equation: 



7(x+3)+5=6(x-2)

We move all terms to the left:

7(x+3)+5-(6(x-2))=0

We multiply parentheses

7x-(6(x-2))+21+5=0



We calculate terms in parentheses: -(6(x-2)), so:

6(x-2)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

7x-(6x-12)+26=0

We get rid of parentheses

7x-6x+12+26=0

We add all the numbers together, and all the variables

x+38=0

We move all terms containing x to the left, all other terms to the right

x=-38

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