7(x+3)+6=11x-4(x-5)

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Solution for 7(x+3)+6=11x-4(x-5) equation:


Simplifying
7(x + 3) + 6 = 11x + -4(x + -5)

Reorder the terms:
7(3 + x) + 6 = 11x + -4(x + -5)
(3 * 7 + x * 7) + 6 = 11x + -4(x + -5)
(21 + 7x) + 6 = 11x + -4(x + -5)

Reorder the terms:
21 + 6 + 7x = 11x + -4(x + -5)

Combine like terms: 21 + 6 = 27
27 + 7x = 11x + -4(x + -5)

Reorder the terms:
27 + 7x = 11x + -4(-5 + x)
27 + 7x = 11x + (-5 * -4 + x * -4)
27 + 7x = 11x + (20 + -4x)

Reorder the terms:
27 + 7x = 20 + 11x + -4x

Combine like terms: 11x + -4x = 7x
27 + 7x = 20 + 7x

Add '-7x' to each side of the equation.
27 + 7x + -7x = 20 + 7x + -7x

Combine like terms: 7x + -7x = 0
27 + 0 = 20 + 7x + -7x
27 = 20 + 7x + -7x

Combine like terms: 7x + -7x = 0
27 = 20 + 0
27 = 20

Solving
27 = 20

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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