7(x+3)-1=2-(x+12)

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Solution for 7(x+3)-1=2-(x+12) equation:



7(x+3)-1=2-(x+12)
We move all terms to the left:
7(x+3)-1-(2-(x+12))=0
We multiply parentheses
7x-(2-(x+12))+21-1=0
We calculate terms in parentheses: -(2-(x+12)), so:
2-(x+12)
determiningTheFunctionDomain -(x+12)+2
We get rid of parentheses
-x-12+2
We add all the numbers together, and all the variables
-1x-10
Back to the equation:
-(-1x-10)
We add all the numbers together, and all the variables
7x-(-1x-10)+20=0
We get rid of parentheses
7x+1x+10+20=0
We add all the numbers together, and all the variables
8x+30=0
We move all terms containing x to the left, all other terms to the right
8x=-30
x=-30/8
x=-3+3/4

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