7(x+3)-8=3x+4(4+x)

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Solution for 7(x+3)-8=3x+4(4+x) equation:



7(x+3)-8=3x+4(4+x)
We move all terms to the left:
7(x+3)-8-(3x+4(4+x))=0
We add all the numbers together, and all the variables
7(x+3)-(3x+4(x+4))-8=0
We multiply parentheses
7x-(3x+4(x+4))+21-8=0
We calculate terms in parentheses: -(3x+4(x+4)), so:
3x+4(x+4)
We multiply parentheses
3x+4x+16
We add all the numbers together, and all the variables
7x+16
Back to the equation:
-(7x+16)
We add all the numbers together, and all the variables
7x-(7x+16)+13=0
We get rid of parentheses
7x-7x-16+13=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation

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