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7(x+3)5x+13=0
We multiply parentheses
35x^2+105x+13=0
a = 35; b = 105; c = +13;
Δ = b2-4ac
Δ = 1052-4·35·13
Δ = 9205
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-\sqrt{9205}}{2*35}=\frac{-105-\sqrt{9205}}{70} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+\sqrt{9205}}{2*35}=\frac{-105+\sqrt{9205}}{70} $
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