7(x+3)=(x-1)+8

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Solution for 7(x+3)=(x-1)+8 equation: 



7(x+3)=(x-1)+8

We move all terms to the left:

7(x+3)-((x-1)+8)=0

We multiply parentheses

7x-((x-1)+8)+21=0



We calculate terms in parentheses: -((x-1)+8), so:

(x-1)+8

We get rid of parentheses

x-1+8

We add all the numbers together, and all the variables

x+7

Back to the equation:

-(x+7)



We get rid of parentheses

7x-x-7+21=0

We add all the numbers together, and all the variables

6x+14=0

We move all terms containing x to the left, all other terms to the right

6x=-14

x=-14/6

x=-2+1/3

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