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7(x+3)=-2(6x-3)+x
We move all terms to the left:
7(x+3)-(-2(6x-3)+x)=0
We multiply parentheses
7x-(-2(6x-3)+x)+21=0
We calculate terms in parentheses: -(-2(6x-3)+x), so:We get rid of parentheses
-2(6x-3)+x
We add all the numbers together, and all the variables
x-2(6x-3)
We multiply parentheses
x-12x+6
We add all the numbers together, and all the variables
-11x+6
Back to the equation:
-(-11x+6)
7x+11x-6+21=0
We add all the numbers together, and all the variables
18x+15=0
We move all terms containing x to the left, all other terms to the right
18x=-15
x=-15/18
x=-5/6
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