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7(x+3)=2(3x+6)
We move all terms to the left:
7(x+3)-(2(3x+6))=0
We multiply parentheses
7x-(2(3x+6))+21=0
We calculate terms in parentheses: -(2(3x+6)), so:We get rid of parentheses
2(3x+6)
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
7x-6x-12+21=0
We add all the numbers together, and all the variables
x+9=0
We move all terms containing x to the left, all other terms to the right
x=-9
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