7(x+3)=2(x-5)

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Solution for 7(x+3)=2(x-5) equation: 



7(x+3)=2(x-5)

We move all terms to the left:

7(x+3)-(2(x-5))=0

We multiply parentheses

7x-(2(x-5))+21=0



We calculate terms in parentheses: -(2(x-5)), so:

2(x-5)

We multiply parentheses

2x-10

Back to the equation:

-(2x-10)



We get rid of parentheses

7x-2x+10+21=0

We add all the numbers together, and all the variables

5x+31=0

We move all terms containing x to the left, all other terms to the right

5x=-31

x=-31/5

x=-6+1/5

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