7(x+3)=9(x-1)+8

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Solution for 7(x+3)=9(x-1)+8 equation: 



7(x+3)=9(x-1)+8

We move all terms to the left:

7(x+3)-(9(x-1)+8)=0

We multiply parentheses

7x-(9(x-1)+8)+21=0



We calculate terms in parentheses: -(9(x-1)+8), so:

9(x-1)+8

We multiply parentheses

9x-9+8

We add all the numbers together, and all the variables

9x-1

Back to the equation:

-(9x-1)



We get rid of parentheses

7x-9x+1+21=0

We add all the numbers together, and all the variables

-2x+22=0

We move all terms containing x to the left, all other terms to the right

-2x=-22

x=-22/-2

x=+11

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