7(x+4)+2=3(4x+5)+15

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Solution for 7(x+4)+2=3(4x+5)+15 equation: 



7(x+4)+2=3(4x+5)+15

We move all terms to the left:

7(x+4)+2-(3(4x+5)+15)=0

We multiply parentheses

7x-(3(4x+5)+15)+28+2=0



We calculate terms in parentheses: -(3(4x+5)+15), so:

3(4x+5)+15

We multiply parentheses

12x+15+15

We add all the numbers together, and all the variables

12x+30

Back to the equation:

-(12x+30)



We add all the numbers together, and all the variables

7x-(12x+30)+30=0

We get rid of parentheses

7x-12x-30+30=0

We add all the numbers together, and all the variables

-5x=0

x=0/-5

x=0

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