7(x+4)+3(x+2)=4(x-1)

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Solution for 7(x+4)+3(x+2)=4(x-1) equation: 



7(x+4)+3(x+2)=4(x-1)

We move all terms to the left:

7(x+4)+3(x+2)-(4(x-1))=0

We multiply parentheses

7x+3x-(4(x-1))+28+6=0



We calculate terms in parentheses: -(4(x-1)), so:

4(x-1)

We multiply parentheses

4x-4

Back to the equation:

-(4x-4)



We add all the numbers together, and all the variables

10x-(4x-4)+34=0

We get rid of parentheses

10x-4x+4+34=0

We add all the numbers together, and all the variables

6x+38=0

We move all terms containing x to the left, all other terms to the right

6x=-38

x=-38/6

x=-6+1/3

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