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7(x+4)+5=2(2x-4)+2
We move all terms to the left:
7(x+4)+5-(2(2x-4)+2)=0
We multiply parentheses
7x-(2(2x-4)+2)+28+5=0
We calculate terms in parentheses: -(2(2x-4)+2), so:We add all the numbers together, and all the variables
2(2x-4)+2
We multiply parentheses
4x-8+2
We add all the numbers together, and all the variables
4x-6
Back to the equation:
-(4x-6)
7x-(4x-6)+33=0
We get rid of parentheses
7x-4x+6+33=0
We add all the numbers together, and all the variables
3x+39=0
We move all terms containing x to the left, all other terms to the right
3x=-39
x=-39/3
x=-13
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