7(x+4)+8(x+4)=7x-7

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Solution for 7(x+4)+8(x+4)=7x-7 equation: 



7(x+4)+8(x+4)=7x-7

We move all terms to the left:

7(x+4)+8(x+4)-(7x-7)=0

We multiply parentheses

7x+8x-(7x-7)+28+32=0

We get rid of parentheses

7x+8x-7x+7+28+32=0

We add all the numbers together, and all the variables

8x+67=0

We move all terms containing x to the left, all other terms to the right

8x=-67

x=-67/8

x=-8+3/8

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