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7(x+4)-2(x-3(5+x)=2/3(x-6)
We move all terms to the left:
7(x+4)-2(x-3(5+x)-(2/3(x-6))=0
Domain of the equation: 3(x-6))!=0We add all the numbers together, and all the variables
x∈R
7(x+4)-2(x-3(x+5)-(2/3(x-6))=0
We multiply parentheses
7x-2(x-3(x+5)-(2/3(x-6))+28=0
We multiply all the terms by the denominator
7x*3(x-6))+28-2(x-3(x+5)-(2=0
We add all the numbers together, and all the variables
7x*3(x-6))+28-2(x-3(x+5)=0
We multiply parentheses
7x*3(x-6))+28-2(x-3x-15=0
Wy multiply elements
21x^2(x-3x-15=0
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