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7(x+4)-8=3x+4(x+5)
We move all terms to the left:
7(x+4)-8-(3x+4(x+5))=0
We multiply parentheses
7x-(3x+4(x+5))+28-8=0
We calculate terms in parentheses: -(3x+4(x+5)), so:We add all the numbers together, and all the variables
3x+4(x+5)
We multiply parentheses
3x+4x+20
We add all the numbers together, and all the variables
7x+20
Back to the equation:
-(7x+20)
7x-(7x+20)+20=0
We get rid of parentheses
7x-7x-20+20=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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