7(x+4)-8x=4(2x+1)-5

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Solution for 7(x+4)-8x=4(2x+1)-5 equation: 



7(x+4)-8x=4(2x+1)-5

We move all terms to the left:

7(x+4)-8x-(4(2x+1)-5)=0

We add all the numbers together, and all the variables

-8x+7(x+4)-(4(2x+1)-5)=0

We multiply parentheses

-8x+7x-(4(2x+1)-5)+28=0



We calculate terms in parentheses: -(4(2x+1)-5), so:

4(2x+1)-5

We multiply parentheses

8x+4-5

We add all the numbers together, and all the variables

8x-1

Back to the equation:

-(8x-1)



We add all the numbers together, and all the variables

-1x-(8x-1)+28=0

We get rid of parentheses

-1x-8x+1+28=0

We add all the numbers together, and all the variables

-9x+29=0

We move all terms containing x to the left, all other terms to the right

-9x=-29

x=-29/-9

x=3+2/9

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