7(x+4)=2(x-5)+3(x+9)

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Solution for 7(x+4)=2(x-5)+3(x+9) equation: 



7(x+4)=2(x-5)+3(x+9)

We move all terms to the left:

7(x+4)-(2(x-5)+3(x+9))=0

We multiply parentheses

7x-(2(x-5)+3(x+9))+28=0



We calculate terms in parentheses: -(2(x-5)+3(x+9)), so:

2(x-5)+3(x+9)

We multiply parentheses

2x+3x-10+27

We add all the numbers together, and all the variables

5x+17

Back to the equation:

-(5x+17)



We get rid of parentheses

7x-5x-17+28=0

We add all the numbers together, and all the variables

2x+11=0

We move all terms containing x to the left, all other terms to the right

2x=-11

x=-11/2

x=-5+1/2

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