7(x+5)+2x-15=2x-10+3(2x-10)-2(x-5)

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Solution for 7(x+5)+2x-15=2x-10+3(2x-10)-2(x-5) equation: 



7(x+5)+2x-15=2x-10+3(2x-10)-2(x-5)

We move all terms to the left:

7(x+5)+2x-15-(2x-10+3(2x-10)-2(x-5))=0

We add all the numbers together, and all the variables

2x+7(x+5)-(2x-10+3(2x-10)-2(x-5))-15=0

We multiply parentheses

2x+7x-(2x-10+3(2x-10)-2(x-5))+35-15=0



We calculate terms in parentheses: -(2x-10+3(2x-10)-2(x-5)), so:

2x-10+3(2x-10)-2(x-5)

determiningTheFunctionDomain
2x+3(2x-10)-2(x-5)-10

We multiply parentheses

2x+6x-2x-30+10-10

We add all the numbers together, and all the variables

6x-30

Back to the equation:

-(6x-30)



We add all the numbers together, and all the variables

9x-(6x-30)+20=0

We get rid of parentheses

9x-6x+30+20=0

We add all the numbers together, and all the variables

3x+50=0

We move all terms containing x to the left, all other terms to the right

3x=-50

x=-50/3

x=-16+2/3

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