7(x+5)+8=11x-4(x-3)

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Solution for 7(x+5)+8=11x-4(x-3) equation:


Simplifying
7(x + 5) + 8 = 11x + -4(x + -3)

Reorder the terms:
7(5 + x) + 8 = 11x + -4(x + -3)
(5 * 7 + x * 7) + 8 = 11x + -4(x + -3)
(35 + 7x) + 8 = 11x + -4(x + -3)

Reorder the terms:
35 + 8 + 7x = 11x + -4(x + -3)

Combine like terms: 35 + 8 = 43
43 + 7x = 11x + -4(x + -3)

Reorder the terms:
43 + 7x = 11x + -4(-3 + x)
43 + 7x = 11x + (-3 * -4 + x * -4)
43 + 7x = 11x + (12 + -4x)

Reorder the terms:
43 + 7x = 12 + 11x + -4x

Combine like terms: 11x + -4x = 7x
43 + 7x = 12 + 7x

Add '-7x' to each side of the equation.
43 + 7x + -7x = 12 + 7x + -7x

Combine like terms: 7x + -7x = 0
43 + 0 = 12 + 7x + -7x
43 = 12 + 7x + -7x

Combine like terms: 7x + -7x = 0
43 = 12 + 0
43 = 12

Solving
43 = 12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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