7(x+5)+x=3(x+3)-8

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Solution for 7(x+5)+x=3(x+3)-8 equation: 



7(x+5)+x=3(x+3)-8

We move all terms to the left:

7(x+5)+x-(3(x+3)-8)=0

We add all the numbers together, and all the variables

x+7(x+5)-(3(x+3)-8)=0

We multiply parentheses

x+7x-(3(x+3)-8)+35=0



We calculate terms in parentheses: -(3(x+3)-8), so:

3(x+3)-8

We multiply parentheses

3x+9-8

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We add all the numbers together, and all the variables

8x-(3x+1)+35=0

We get rid of parentheses

8x-3x-1+35=0

We add all the numbers together, and all the variables

5x+34=0

We move all terms containing x to the left, all other terms to the right

5x=-34

x=-34/5

x=-6+4/5

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