7(x+5)+x=3(x+3)-8

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Solution for 7(x+5)+x=3(x+3)-8 equation:



7(x+5)+x=3(x+3)-8
We move all terms to the left:
7(x+5)+x-(3(x+3)-8)=0
We add all the numbers together, and all the variables
x+7(x+5)-(3(x+3)-8)=0
We multiply parentheses
x+7x-(3(x+3)-8)+35=0
We calculate terms in parentheses: -(3(x+3)-8), so:
3(x+3)-8
We multiply parentheses
3x+9-8
We add all the numbers together, and all the variables
3x+1
Back to the equation:
-(3x+1)
We add all the numbers together, and all the variables
8x-(3x+1)+35=0
We get rid of parentheses
8x-3x-1+35=0
We add all the numbers together, and all the variables
5x+34=0
We move all terms containing x to the left, all other terms to the right
5x=-34
x=-34/5
x=-6+4/5

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