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7(x+5)-3(2x+3)=33
We move all terms to the left:
7(x+5)-3(2x+3)-(33)=0
We multiply parentheses
7x-6x+35-9-33=0
We add all the numbers together, and all the variables
x-7=0
We move all terms containing x to the left, all other terms to the right
x=7
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