7(x+5)-3=4+2(x-1)

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Solution for 7(x+5)-3=4+2(x-1) equation:



7(x+5)-3=4+2(x-1)
We move all terms to the left:
7(x+5)-3-(4+2(x-1))=0
We multiply parentheses
7x-(4+2(x-1))+35-3=0
We calculate terms in parentheses: -(4+2(x-1)), so:
4+2(x-1)
determiningTheFunctionDomain 2(x-1)+4
We multiply parentheses
2x-2+4
We add all the numbers together, and all the variables
2x+2
Back to the equation:
-(2x+2)
We add all the numbers together, and all the variables
7x-(2x+2)+32=0
We get rid of parentheses
7x-2x-2+32=0
We add all the numbers together, and all the variables
5x+30=0
We move all terms containing x to the left, all other terms to the right
5x=-30
x=-30/5
x=-6

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